{"id":2190,"date":"2013-04-30T14:44:43","date_gmt":"2013-04-30T14:44:43","guid":{"rendered":"\/2013\/04\/30\/sabit-sacl-s-l-kaynakl-koeruekler\/"},"modified":"2021-06-24T15:53:17","modified_gmt":"2021-06-24T15:53:17","slug":"sabit-sacl-s-l-kaynakl-koeruekler","status":"publish","type":"post","link":"https:\/\/www.pei.it\/tr\/bez-korukler-standart-uru%cc%88nler\/sabit-sacl-s-l-kaynakl-koeruekler\/","title":{"rendered":"Sabit sacl\u0131 \u0131s\u0131l kaynakl\u0131 k\u00f6r\u00fckler"},"content":{"rendered":"
1)<\/span> Flan\u015f 1 <\/p>\n P.A. = <\/span>A\u00e7\u0131k boy x(mm)<\/span> 15 20 25 30 35 40 45 * malzemeler bak\u0131n\u0131z<\/a><\/p>\n<\/div>\n <\/p>\n * We hypothesize the fabric material with code \u201cTEMAT151\u201d (malzemeler bak\u0131n\u0131z<\/a>) \u00c7al\u0131\u015fma pozisyonu: Yatay, Dikey ve Cephesel 1) Flan\u015f 1 2)\u00a0Takviye 3)\u00a0K\u00f6ru\u0308k malzemesi 4) Flan\u015f 2 5) Montaj i\u00e7in sadece ilk sac hareketli olarak yap\u0131labilir P.A. = A\u00e7\u0131k boy B = D\u0131\u015f geni\u015flik P.C. = Kapal\u0131 boy Stroke = A\u00e7\u0131k boy \u2013 Kapal\u0131 boy a = D\u0131\u015f y\u00fckseklik x = Dilim derinli\u011fi x(mm) 15 20 25 […]<\/p>\n","protected":false},"author":1,"featured_media":2122,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[377],"tags":[],"acf":[],"yoast_head":"\n
\n2)<\/span>\u00a0Takviye
\n3)<\/span>\u00a0K\u00f6ru\u0308k malzemesi
\n4)<\/span> Flan\u015f 2
\n5)<\/strong> Montaj i\u00e7in sadece ilk sac hareketli olarak yap\u0131labilir<\/p>\n
\nB = <\/span>D\u0131\u015f geni\u015flik
\n<\/span>P.C. = <\/span>Kapal\u0131 boy
\nStroke = <\/span>A\u00e7\u0131k boy \u2013 Kapal\u0131 boy
\na = <\/span>D\u0131\u015f y\u00fckseklik
\nx = <\/span>Dilim derinli\u011fi<\/p>\n
\nL(mm)<\/span> 16 21 26 33 43 48 56
\nZ(mm)<\/span> 45 55 65 75 85 95 105<\/p>\nKAPALI BOYUN Hesaplanma Formul\u00fc<\/h3>\n
\nSM<\/span> = Fabric thickness *
\nSS<\/span> = Stiffener thickness *
\nSF<\/span> = Flange thickness *
\nNP<\/span> = Number of folds = (P.A.: AP) + 2
\nP. C<\/span>.= (SM . 8 + SS) . NP + (SF . 2)<\/div>\n
\n** We hypothesize that the stiffener is 1 mm thick
\n*** We hypothesize that the flange is 2 mm thick (malzemeler bak\u0131n\u0131z<\/a>)<\/p>\n","protected":false},"excerpt":{"rendered":"